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Kaustubh January 21, 2011 at 11:56 am
answer is (a)1/3
ankur bhatnagar January 21, 2011 at 9:40 pm
might be “D”
let put x=cos^2/3q and solve finally u will come to the equation containing log and sin term we can solve it by using their expansion.
Rameez June 24, 2011 at 10:11 am
put 1-X^3 as t^2…………
Rameez June 24, 2011 at 10:48 am
sorryy …………ans ….is……. A
anish June 24, 2011 at 12:08 pm
diff the right hand side….might help
Ashwin Shridhar June 24, 2011 at 4:48 pm
In this problem put 1-x^3=t then -3x^2 dx=dt. Now multiply and divide with x now evaluate dx/x put x^3=1-t you’ll get dx/x=-dt/3(1-t) . Now solve the New integral by again putting t=u^2 and you’ll get the answer as 1/3 !!!!
samir June 24, 2011 at 8:37 pm
samir June 24, 2011 at 8:38 pm
1/3 that is ‘a’!!!!!
put x^3/2 =t…n thn simplify!!
Shubham Agarwal June 25, 2011 at 9:17 am
Ans: (D) -2/3
put (1-x^3)^1/2 as t^2
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