### 21 Jan

**By**pradeep**In**Question of The Day**Comments**9

Tags: 2011, 2012, 2103, calculus, Daily, DPP, IIT JEE, IITian, IITJEE, indefinite, integration, Math, mathematics, Maths, practice problem, problems, question, Question of The Day

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Home » Blog » Question of The Day » DPP – Indefinite Integration

**By**pradeep**In**Question of The Day**Comments**9

Tags: 2011, 2012, 2103, calculus, Daily, DPP, IIT JEE, IITian, IITJEE, indefinite, integration, Math, mathematics, Maths, practice problem, problems, question, Question of The Day

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Kaustubh January 21, 2011 at 11:56 am

answer is (a)1/3

ankur bhatnagar January 21, 2011 at 9:40 pm

might be “D”

let put x=cos^2/3q and solve finally u will come to the equation containing log and sin term we can solve it by using their expansion.

Rameez June 24, 2011 at 10:11 am

Ans–D

put 1-X^3 as t^2…………

Rameez June 24, 2011 at 10:48 am

sorryy …………ans ….is……. A

anish June 24, 2011 at 12:08 pm

diff the right hand side….might help

Ashwin Shridhar June 24, 2011 at 4:48 pm

In this problem put 1-x^3=t then -3x^2 dx=dt. Now multiply and divide with x now evaluate dx/x put x^3=1-t you’ll get dx/x=-dt/3(1-t) . Now solve the New integral by again putting t=u^2 and you’ll get the answer as 1/3 !!!!

samir June 24, 2011 at 8:37 pm

a= 1/3!!!!

samir June 24, 2011 at 8:38 pm

1/3 that is ‘a’!!!!!

put x^3/2 =t…n thn simplify!!

Shubham Agarwal June 25, 2011 at 9:17 am

Ans: (D) -2/3

put (1-x^3)^1/2 as t^2